while(*str++ != '\0')死循环分析
第一种情况:第一个字符’1’没有被覆盖死循环 char str1[20] = "1234567890"; char *str = str1; while( *str++ != '\0' ){ *str = '9'; printf("str1 = %s\n", str1); } str1 = 19999999999999999999999999999999999999...