python对于java中Map按value排序的快速实现
l=[1,2,3,4,5,6,1,2,3,5,6]d={}for index in range(len(l)): if l[index] in d: d[l[index]]=d.get(l[index])+1 else: d[l[index]]=1l=sorted(d.items(),key = lambda x:x[1],reverse ...
