概述
一年一度的春运又来了,
今年我自己写了个抢票脚本。
python +splinter自动刷新抢票,可以成功抢到(依赖自己的网络环境太厉害,还有机器的好坏),
但是感觉不是很完美,
有大神请指导完善一下(或者有没有别的好点的思路)
不胜感谢
# -*- coding: utf-8 -*-
"""
@author: liuyw
"""
from splinter.browser import Browser
from time import sleep
import traceback
import time, sys
class huoche(object):
"""docstring for huoche"""
driver_name=''
executable_path=''
#用户名,密码
username = u"xxx@qq.com"
passwd = u"xxxx"
# cookies值得自己去找, 下面两个分别是上海, 太原南
starts = u"%u4E0A%u6D77%2CSHH"
ends = u"%u592A%u539F%2CTYV"
# 时间格式2018-01-19
dtime = u"2018-01-19"
# 车次,选择第几趟,0则从上之下依次点击
order = 0
###乘客名
users = [u"xxx",u"xxx"]
##席位
xb = u"二等座"
pz=u"成人票"
"""网址"""
ticket_url = "https://kyfw.12306.cn/otn/leftTicket/init"
login_url = "https://kyfw.12306.cn/otn/login/init"
initmy_url = "https://kyfw.12306.cn/otn/index/initMy12306"
buy="https://kyfw.12306.cn/otn/confirmPassenger/initDc"
login_url='https://kyfw.12306.cn/otn/login/init'
def __init__(self):
self.driver_name='chrome'
self.executable_path='/usr/local/bin/chromedriver'
def login(self):
self.driver.visit(self.login_url)
self.driver.fill("loginUserDTO.user_name", self.username)
# sleep(1)
self.driver.fill("userDTO.password", self.passwd)
print u"等待验证码,自行输入..."
while True:
if self.driver.url != self.initmy_url:
sleep(1)
else:
break
def start(self):
self.driver=Browser(driver_name=self.driver_name,executable_path=self.executable_path)
self.driver.driver.set_window_size(1400, 1000)
self.login()
# sleep(1)
self.driver.visit(self.ticket_url)
try:
print u"购票页面开始..."
# sleep(1)
# 加载查询信息
self.driver.cookies.add({"_jc_save_fromStation": self.starts})
self.driver.cookies.add({"_jc_save_toStation": self.ends})
self.driver.cookies.add({"_jc_save_fromDate": self.dtime})
self.driver.reload()
count=0
if self.order!=0:
while self.driver.url==self.ticket_url:
self.driver.find_by_text(u"查询").click()
count += 1
print u"循环点击查询... 第 %s 次" % count
# sleep(1)
try:
self.driver.find_by_text(u"预订")[self.order - 1].click()
except Exception as e:
print e
print u"还没开始预订"
continue
else:
while self.driver.url == self.ticket_url:
self.driver.find_by_text(u"查询").click()
count += 1
print u"循环点击查询... 第 %s 次" % count
# sleep(0.8)
try:
for i in self.driver.find_by_text(u"预订"):
i.click()
sleep(1)
except Exception as e:
print e
print u"还没开始预订 %s" %count
continue
print u"开始预订..."
# sleep(3)
# self.driver.reload()
sleep(1)
print u'开始选择用户...'
for user in self.users:
self.driver.find_by_text(user).last.click()
print u"提交订单..."
sleep(1)
# self.driver.find_by_text(self.pz).click()
# self.driver.find_by_id('').select(self.pz)
# # sleep(1)
# self.driver.find_by_text(self.xb).click()
# sleep(1)
self.driver.find_by_id('submitOrder_id').click()
# print u"开始选座..."
# self.driver.find_by_id('1D').last.click()
# self.driver.find_by_id('1F').last.click()
sleep(1.5)
print u"确认选座..."
self.driver.find_by_id('qr_submit_id').click()
except Exception as e:
print e
if __name__ == '__main__':
huoche=huoche()
huoche.start()
最后
以上就是爱听歌月饼为你收集整理的 python +splinter自动刷新抢票的全部内容,希望文章能够帮你解决 python +splinter自动刷新抢票所遇到的程序开发问题。
如果觉得靠谱客网站的内容还不错,欢迎将靠谱客网站推荐给程序员好友。
本图文内容来源于网友提供,作为学习参考使用,或来自网络收集整理,版权属于原作者所有。
发表评论 取消回复