java参数错误_java参数不对怎么弄

//Abytecan'tholdavaluehigherthan127//ThisprogramthrowsanArithmeticException//ifaddingtwobytesyieldsavaluethatistoohighpublicclassDebugTwelve2{publicstaticvoidmain(String[...

// A byte can't hold a value higher than 127

// This program throws an ArithmeticException

// if adding two bytes yields a value that is too high

public class DebugTwelve2

{

public static void main(String[] args)

{

byte num1 = 120, num2 = 120, result;

final byte HIGHBYTE = 127;

try

{

allowed = (byte)(HIGHBYTE - num1);

if(num2 > allowed)

throw(new ArithmeticException);

result = (byte)(num1 + num2);

System.out.println("Result is " + result);

}

catch(ArithmeticException error)

{

System.out.println(Byte can't hold value higher than + HIGHBYTE);

}

}

}

---------- compiler ----------

DebugTwelve2.java:14: 错误: 需要'('或'['

throw(new ArithmeticException);

^

DebugTwelve2.java:20: 错误: 需要')'

System.out.println(Byte can't hold value higher than + HIGHBYTE);

^

DebugTwelve2.java:20: 错误: 未结束的字符文字

System.out.println(Byte can't hold value higher than + HIGHBYTE);

^

DebugTwelve2.java:20: 错误: 需要';'

System.out.println(Byte can't hold value higher than + HIGHBYTE);

^

DebugTwelve2.java:20: 错误: 需要';'

System.out.println(Byte can't hold value higher than + HIGHBYTE);

^

DebugTwelve2.java:20: 错误: 不是语句

System.out.println(Byte can't hold value higher than + HIGHBYTE);

^

DebugTwelve2.java:20: 错误: 需要';'

System.out.println(Byte can't hold value higher than + HIGHBYTE);

^

7 个错误

输出完成 (耗时 2 秒) - 正常终止

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