第四章第十一题（十进制转十六进制）(Decimal to hex)

• *4.11（十进制转十六进制）编写一个程序，提示用户输入0~15之间的一个整数，显示其对应的十六进制数。对于不正确的输入数字，提示非法输入。
  下面是一个运行示例：
  Enter a decimal value (0 to 15): 11
  The hex value is B
  Enter a decimal value (0 to 15): 5
  The hex value is 5
  Enter a decimal value (0 to 15): 31
  31 is an invalid input

  *4.11(Decimal to hex) Write a program that prompts the user to enter decimal digits and displays its corresponding hex value.
  Here are some sample runs:
  Enter a decimal value (0 to 15): 11
  The hex value is B
  Enter a decimal value (0 to 15): 5
  The hex value is 5
  Enter a decimal value (0 to 15): 31
  31 is an invalid input

• 参考代码：

package chapter04;

import java.util.Scanner;

public class Code_11 {
    public static void main(String[] args) {
        int deciNum;

        System.out.print("Enter a decimal value (0 to 15): ");
        Scanner input = new Scanner(System.in);
        deciNum = input.nextInt();

        if(0 <= deciNum && deciNum <= 9)
            System.out.println("The hex value is " + deciNum);
        else if(10 <= deciNum && deciNum <= 15)
            System.out.printf("The hex value is %c", (deciNum - 10 + 'A'));
        else
            System.out.println(deciNum + " is an invalid input");

        input.close();
    }
}

• 结果显示：

Enter a decimal value (0 to 15): 11
The hex value is B
Process finished with exit code 0

最后

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