概述
I've made this code to convert whole base 10 numbers into binary. The code I believe is everything that it needs to be but I can't get me ArrayLists to work. I've spent a few hours on this site and other trying countless changes to no avail. I've gotten the code to compile without and errors but as soon as I enter an int the program crashes.
Here is the code:
import java.util.Scanner;
import java.util.ArrayList;
public class BinaryConverter {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
ArrayList binary = new ArrayList();
int a = in.nextInt();
binary = binaryConverter(a);
for (int i = binary.size(); i > -1; i = i - 1){
System.out.print(binary.get(i));
}
}
public static ArrayList binaryConverter(Integer n) {
ArrayList remainder = new ArrayList();
while (n/2 != 0) {
remainder.add(n%2);
n = n/2;
}
remainder.add(n%2);
return remainder;
}
}
These are the exceptions java throws at me when I input a number.
Jons-iMac:java jon$ java BinaryConverter
142
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index 8 out-of-bounds for length 8
at java.base/jdk.internal.util.Preconditions.outOfBounds(Preconditions.java:64)
at java.base/jdk.internal.util.Preconditions.outOfBoundsCheckIndex(Preconditions.java:70)
at java.base/jdk.internal.util.Preconditions.checkIndex(Preconditions.java:248)
at java.base/java.util.Objects.checkIndex(Objects.java:372)
at java.base/java.util.ArrayList.get(ArrayList.java:440)
at BinaryConverter.main(BinaryConverter.java:16)
I hope this is enough information.
解决方案
In your code you get the value by index which is evaluated incorrectly.
for (int i = binary.size(); i > -1; i = i - 1){
System.out.print(binary.get(i));
}
Assignment of binary.size() indeed out of bounds, because indexes counted from binary.size() to zero, but it is out of range which is bound from zero to binary.size()-1.
最后
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