概述
编码过程:
假设有一个4*4数据块
{
0, 3, -1, 0,
0, -1, 1, 0,
1, 0, 0, 0,
0, 0, 0, 0
}
数据重排列:0,3,0,1,-1,-1,0,1,0……
1) 初始值设定:
非零系数的数目(TotalCoeffs) = 5;
拖尾系数的数目(TrailingOnes)= 3;
最后一个非零系数前零的数目(Total_zeros) = 3;
变量NC=1;
(说明:NC值的确定:色度的直流系数NC=-1;其他系数类型NC值是根据当前块左边4*4块的非零系数数目(NA)当前块上面4*4块的非零系数数目(NB)求得的,见毕厚杰书P120表6.10)
suffixLength = 0;
i = TotalCoeffs = 5;
2) 编码coeff_token:
查标准(BS ISO/IEC 14496-10:2003)Table 9-5,可得:
If (TotalCoeffs == 5 && TrailingOnes == 3 && 0 <= NC < 2)
coeff_token = 0000 100;
Code = 0000 100;
3) 编码所有TrailingOnes的符号:
逆序编码,三个拖尾系数的符号依次是+(0),-(1),-(1);
即:
TrailingOne sign[i--] = 0;
TrailingOne sign[i--] = 1;
TrailingOne sign[i--] = 1;
Code = 0000 1000 11;
4) 编码除了拖尾系数以外非零系数幅值Levels:
过程如下:
(1)将有符号的Level[ i ]转换成无符号的levelCode;
如果Level[ i ]是正的,levelCode = (Level[ i ]<<1) – 2;
如果Level[ i ]是负的,levelCode = - (Level[ i ]<<1) – 1;
(2)计算level_prefix:level_prefix = levelCode / (1<<suffixLength);
查表9-6可得所对应的bit string;
(3)计算level_suffix:level_suffix = levelCode % (1<<suffixLength);
(4)根据suffixLength的值来确定后缀的长度;
(5)suffixLength updata:
If ( suffixLength == 0 )
suffixLength++;
else if ( levelCode > (3<<suffixLength-1) && suffixLength <6)
suffixLength++;
回到例子中,依然按照逆序,Level[i--] = 1;(此时i = 1)
levelCode = 0;level_prefix = 0;
查表9-6,可得level_prefix = 0时对应的bit string = 1;
因为suffixLength初始化为0,故该Level没有后缀;
因为suffixLength = 0,故suffixLength++;
Code = 0000 1000 111;
编码下一个Level:Level[0] = 3;
levelCode = 4;level_prefix = 2;查表得bit string = 001;
level_suffix = 0;suffixLength = 1;故码流为0010;
Code = 0000 1000 1110 010;
i = 0,编码Level结束。
5)编码最后一个非零系数前零的数目(TotalZeros):
查表9-7,当TotalCoeffs = 5,total_zero = 3时,bit string = 111;
Code = 0000 1000 1110 0101 11;
6) 对每个非零系数前零的个数(RunBefore)进行编码:
i = TotalCoeffs = 5;ZerosLeft = Total_zeros = 3;查表9-10:
依然按照逆序编码
ZerosLeft =3, run_before = 1 run_before[4]=10;
ZerosLeft =2, run_before = 0 run_before[3]=1;
ZerosLeft =2, run_before = 0 run_before[2]=1;
ZerosLeft =2, run_before = 1 run_before[1]=01;
ZerosLeft =1, run_before = 1 run_before[0]不需要码流来表示
Code = 0000 1000 1110 0101 1110 1101;
编码完毕。
最后
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