Verilog写一个时钟

题目：

Create a set of counters suitable for use as a 12-hour clock (with am/pm indicator). Your counters are clocked by a fast-running clk, with a pulse on ena whenever your clock should increment (i.e., once per second).
reset resets the clock to 12:00 AM. pm is 0 for AM and 1 for PM. hh, mm, and ss are two BCD (Binary-Coded Decimal) digits each for hours (01-12), minutes (00-59), and seconds (00-59). Reset has higher priority than enable, and can occur even when not enabled.
The following timing diagram shows the rollover behaviour from 11:59:59 AM to 12:00:00 PM and the synchronous reset and enable behaviour.

分析：实际上还是考察计数进位，需要注意的事pm反转是在11:59:59，刚开始以为是12:59:59呢，另外，我觉得8位的ss作为秒数的统计，我觉得不需要分低4位和高4位，那样反而麻烦，mm和hh也是如此。写的代码如下
代码：

module top_module(
    input 

最后

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