我是靠谱客的博主 娇气鱼,最近开发中收集的这篇文章主要介绍c语言 eval,C语言定义了一个数组,调试时显示expression cannot be evalued,求教高手...,觉得挺不错的,现在分享给大家,希望可以做个参考。

概述

C语言定义了一个数组,调试时显示expression cannot be evalued,求教高手0

00e27ab806e4881f8254fe7ae8741834.pngcskm15742014.02.11浏览66次分享举报

#include

void main()

{

int i,j,t,k,z[4];

int s_in1[49],s_out[32],p_out[32];

int r[8],c[8];

int s_he[8];

int P[32] = {15,6,19,20,28,11,27,16, //p盒

0,14,22,25,4,17,30,9,

1,7,23,13,31,26,2,8,

18,12,29,5,21,10,3,24};

int S[8][4][16]={{{14,4,13,1,2,15,11,8,3,10,6,12,5,9,0,7}, //s盒

{0,15,7,4,14,2,13,1,10,6,12,11,9,5,3,8},

{4,1,14,8,13,6,2,11,15,12,9,7,3,10,5,0},

{15,12,8,2,4,9,1,7,5,11,3,14,10,0,6,13}},

//S2

{{15,1,8,14,6,11,3,4,9,7,2,13,12,0,5,10},

{3,13,4,7,15,2,8,14,12,0,1,10,6,9,11,5},

{0,14,7,11,10,4,13,1,5,8,12,6,9,3,2,15},

{13,8,10,1,3,15,4,2,11,6,7,12,0,5,14,9}},

//S3

{{10,0,9,14,6,3,15,5,1,13,12,7,11,4,2,8},

{13,7,0,9,3,4,6,10,2,8,5,14,12,11,15,1},

{13,6,4,9,8,15,3,0,11,1,2,12,5,10,14,7},

{1,10,13,0,6,9,8,7,4,15,14,3,11,5,2,12}},

//S4

{{7,13,14,3,0,6,9,10,1,2,8,5,11,12,4,15},

{13,8,11,5,6,15,0,3,4,7,2,12,1,10,14,9},

{10,6,9,0,12,11,7,13,15,1,3,14,5,2,8,4},

{3,15,0,6,10,1,13,8,9,4,5,11,12,7,2,14}},

//S5

{{2,12,4,1,7,10,11,6,8,5,3,15,13,0,14,9},

{14,11,2,12,4,7,13,1,5,0,15,10,3,9,8,6},

{4,2,1,11,10,13,7,8,15,9,12,5,6,3,0,14},

{11,8,12,7,1,14,2,13,6,15,0,9,10,4,5,3}},

//S6

{{12,1,10,15,9,2,6,8,0,13,3,4,14,7,5,11},

{10,15,4,2,7,12,9,5,6,1,13,14,0,11,3,8},

{9,14,15,5,2,8,12,3,7,0,4,10,1,13,11,6},

{4,3,2,12,9,5,15,10,11,14,1,7,6,0,8,13}},

//S7

{{4,11,2,14,15,0,8,13,3,12,9,7,5,10,6,1},

{13,0,11,7,4,9,1,10,14,3,5,12,2,15,8,6},

{1,4,11,13,12,3,7,14,10,15,6,8,0,5,9,2},

{6,11,13,8,1,4,10,7,9,5,0,15,14,2,3,12}},

//S8

{{13,2,8,4,6,15,11,1,10,9,3,14,5,0,12,7},

{1,15,13,8,10,3,7,4,12,5,6,11,0,14,9,2},

{7,11,4,1,9,12,14,2,0,6,10,13,15,3,5,8},

{2,1,14,7,4,10,8,13,15,12,9,0,3,5,6,11}}};

printf("请输入48比特:");

scanf("%s",s_in1);

for (i=0,j=0;i<=48;i+=6,j++)//将48比特转为S的行号和列号,r行号,c列号

{

r[j]=s_in1[i]*2+s_in1[i+5];

c[j]=s_in1[i+1]*8+s_in1[i+2]*4+s_in1[i+3]*2+s_in1[i+4];

}

for(i=0;i<9;i++)//转换为S盒中的十进制数字,s_he存放

{

t=r[i];

k=c[i];

s_he[i]=S[i][t][k];

}

for(i=0,k=0;i<9;i++,k=k+4)//将十进制数字转换为二进制

{

for(j=0;j<=4;j++)

{

z[i]=s_he[i]%2;

}

for(j=0;j<=4;j++)

{

s_out[k+j]=z[3-j];

}

}

for(i=0;i<33;i++)//p盒置换

{

t=P[i];

p_out[i]=s_out[t];

}

for(i=0;i<=33;i++)//输出p盒

{

printf("%d",p_out[i]);

}

return;

}

s_in1有错误,显示表达式不能赋值,怎么回事啊

最后

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