C/C++ int数与多枚举值互转的实现

#include <iostream>

using namespace std;


int nFlag = 0; //用移位表示各个枚举的开关
typedef enum
{
    TYPEA, //A开启，则nflag为1=0x00000001
    TYPEB, //B开启，则nflag为2=0x00000010
    TYPEC, //C开启，则nflag为4=0x00000100
    TYPED, //D开启，则nflag为8=0x00001000
    TYPENUM //枚举最大值，计数用
}EMTypeNum;

void int2enum (int n)
{
    if(n&(0x01<<TYPEA))
    {
     //为真
     cout << "TYPEA is ONn";
    }
    else
    {
     //为假
     cout << "TYPEA is OFFn";
    }
    
    if(n&(0x01<<TYPEB))
    {
     //为真
     cout << "TYPEB is ONn";
    }
    else
    {
     //为假
     cout << "TYPEB is OFFn";
    }
    
    if(n&(0x01<<TYPEC))
    {
     //为真
     cout << "TYPEC is ONn";
    }
    else
    {
     //为假
     cout << "TYPEC is OFFn";
    }

    if(n&(0x01<<TYPED))
    {
     //为真
     cout << "TYPED is ONn";
    }
    else
    {
     //为假
     cout << "TYPED is OFFn";
    }      
} 

void enum2int(EMTypeNum eMType, bool bOn)
{
    if(bOn)
    {
        nFlag |= (0x01 << eMType);
    }
    else
    {
        nFlag &= ~(0x01 << eMType);
    }
    cout << "nFlag:" << nFlag << endl;
}

int main() {

    int i = 0;
    for(i = 0; i < TYPENUM;i++)
    {
        enum2int((EMTypeNum)i, true);
        int2enum(nFlag);
        cout << endl;
    }
    
    
    for(i = 0; i < TYPENUM;i++)
    {
        enum2int((EMTypeNum)i, false);
        int2enum(nFlag); 
        cout << endl;
    }
    
    return 0;
}