C语言编写五子棋游戏

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我是靠谱客的博主俊秀萝莉，最近开发中收集的这篇文章主要介绍C语言编写五子棋游戏，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

本文实例为大家分享了C语言编写五子棋游戏的具体代码，供大家参考，具体内容如下

一、构建棋盘

首先可以用一个二维数组来构建棋盘，下标表示位置，内容表示黑子白子或者空位。当数组内容为1时，该位置为白字，当数组为0时，该位置为白子，空位输出+

int w[11][11], flag = 0;
 int a, b;
 
 for (int k = 0; k < 11; k++)
   printf("第%d列t", k);
  printf("n");
  for (int i = 0; i < 11; i++) {
   for (int j = 0; j < 11; j++) {
    if (w[i][j] == 0) printf("黑t");
    else if (w[i][j] == 1) printf("白t");
    else printf("+t");
   }
   printf("第%d行nn", i);
  }

二、判断位置超范围与错误输入

当输入的棋子坐标超出范围或者该位置已经存在棋子，则再次输入棋子坐标。其中flag作为标志作为判别黑手白手的标志。

if (flag == 0) {
   printf("黑色下棋n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范围，请重新输入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)   
   {
    printf("此位置已有棋子，请重新输入：");
    scanf("%d %d", &a, &b);
   }
   flag = 1;
   w[a][b] = 0;
  }
  else {
   printf("白色下棋n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范围，请重新输入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)
   {
    printf("此位置已有棋子，请重新输入：");
    scanf("%d %d", &a, &b);
   }

三、判断胜负

在五子棋中，出现五个棋子排成一排或者一列或者斜排即可判为胜出。每当落下一个棋子，对该棋子前后上下斜排五个棋子进行判别，超过五个连续的一样颜色的棋子则胜出。

int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
  int x = 1, y = 1, m = 1, n = 1;
  if (w[a][b] == 1) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 1) A++;
    else break;    
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 1) A++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a+i][b] == 1) C++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 1) C++;
    else break;
   }
   if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a+i][b + i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a-i][b - i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b-i] == 1) y++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b+i] == 1) y++;
     else break;
    }
    if (x > 4 || y > 4) jieguo = 1;
   }
  }
  if (w[a][b] == 0) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a + i][b] == 0) D++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 0) D++;
    else break;
   }
   if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a + i][b + i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a - i][b - i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b - i] == 0) n++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b + i] == 0) n++;
     else break;
    }
    if (m > 4 || n > 4) jieguo = 2;
   }
  }

程序完成

四、演示结果

五、源代码

int main() {
 int w[11][11], flag = 0;
 int a, b;
 while (1) {
  if (flag == 0) {
   printf("黑色下棋n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范围，请重新输入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)   
   {
    printf("此位置已有棋子，请重新输入：");
    scanf("%d %d", &a, &b);
   }
   flag = 1;
   w[a][b] = 0;
  }
  else {
   printf("白色下棋n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范围，请重新输入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)
   {
    printf("此位置已有棋子，请重新输入：");
    scanf("%d %d", &a, &b);
   }
   flag = 0;
   w[a][b] = 1;
  }
  
  int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
  int x = 1, y = 1, m = 1, n = 1;
  if (w[a][b] == 1) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 1) A++;
    else break;    
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 1) A++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a+i][b] == 1) C++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 1) C++;
    else break;
   }
   if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a+i][b + i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a-i][b - i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b-i] == 1) y++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b+i] == 1) y++;
     else break;
    }
    if (x > 4 || y > 4) jieguo = 1;
   }
  }
  if (w[a][b] == 0) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a + i][b] == 0) D++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 0) D++;
    else break;
   }
   if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a + i][b + i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a - i][b - i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b - i] == 0) n++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b + i] == 0) n++;
     else break;
    }
    if (m > 4 || n > 4) jieguo = 2;
   }
  }
 
  for (int k = 0; k < 11; k++)
   printf("第%d列t", k);
  printf("n");
  for (int i = 0; i < 11; i++) {
   for (int j = 0; j < 11; j++) {
    if (w[i][j] == 0) printf("黑t");
    else if (w[i][j] == 1) printf("白t");
    else printf("+t");
   }
   printf("第%d行nn", i);
  }
  if (jieguo == 1) {
   printf("白棋胜利");
   break;
  }
  if (jieguo == 2) {
   printf("黑棋胜利");
   break;
  }
 }
 return 0;
}

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