C语言中指针的加减运算方法示例

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char arr[3];
 printf("arr:n%dn%dn%dn", arr, arr + 1, arr + 2);
 char *parr[3];
 printf("parr:n%dn%dn%dn", parr, parr + 1, parr + 2);

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char a = 'a', b = 'b', c = 'c', d = 'd';
 char *arr[20] = {&a,&b,&c,&d};
 char **parr = arr; //arr的类型也是char**
 char *str;
 printf("&a:%d,&b:%d,&c:%d,&d:%dn", &a, &b, &c, &d);
 printf("&arr[0]:%d,&arr[1]:%d,&arr[2]:%d,&arr[3]:%dn", &arr[0], &arr[1], &arr[2], &arr[3]);
 printf("arr:%d,parr:%dn", arr,parr);
 printf("*parr:%d,**parr:%cn", *parr, **parr);
 str = *parr; //arr[0]，char*类型
 printf("----- str=*parr -----n");
 printf("str:%d,*str:%cn", str, *str);
 str++; 
 printf("----- str++ -----n");
 printf("str:%d,*str:%cn", str, *str);
 
 str = *(parr + 1);
 printf("----- str=*(parr+1) -----n");
 printf("str:%d,*str:%cn", str, *str);
 str = *(parr + 2); //*(arr+2*4)
 printf("----- str=*(parr+2) -----n");
 printf("str:%d,*str:%cn", str, *str);