javascript或asp实现的判断身份证号码是否正确两种验证方法

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我是靠谱客的博主天真西装，最近开发中收集的这篇文章主要介绍javascript或asp实现的判断身份证号码是否正确两种验证方法，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

具体代码如下：

一、用javascript验证：

复制代码代码如下:

 
<script> 
function checkIdcard(idcard){ 
var Errors=new Array( 
"验证通过!", 
"身份证号码位数不对!", 
"身份证号码出生日期超出范围或含有非法字符!", 
"身份证号码校验错误!", 
"身份证地区非法!" 
); 
var area={11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"} 

var idcard,Y,JYM; 
var S,M; 
var idcard_array = new Array(); 
idcard_array = idcard.split(""); 
//地区检验 
if(area[parseInt(idcard.substr(0,2))]==null) return Errors[4]; 
//身份号码位数及格式检验 
switch(idcard.length){ 
case 15: 
if ( (parseInt(idcard.substr(6,2))+1900) % 4 == 0 || ((parseInt(idcard.substr(6,2))+1900) % 100 == 0 && (parseInt(idcard.substr(6,2))+1900) % 4 == 0 )){ 
ereg=/^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$/;//测试出生日期的合法性 
} else { 
ereg=/^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$/;//测试出生日期的合法性 
} 
if(ereg.test(idcard)) return Errors[0]; 
else return Errors[2]; 
break; 
case 18: 
//18位身份号码检测 
//出生日期的合法性检查 
//闰年月日:((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9])) 
//平年月日:((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8])) 
if ( parseInt(idcard.substr(6,4)) % 4 == 0 || (parseInt(idcard.substr(6,4)) % 100 == 0 && parseInt(idcard.substr(6,4))%4 == 0 )){ 
ereg=/^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$/;//闰年出生日期的合法性正则表达式 
} else { 
ereg=/^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$/;//平年出生日期的合法性正则表达式 
} 
if(ereg.test(idcard)){//测试出生日期的合法性 
//计算校验位 
S = (parseInt(idcard_array[0]) + parseInt(idcard_array[10])) * 7 
+ (parseInt(idcard_array[1]) + parseInt(idcard_array[11])) * 9 
+ (parseInt(idcard_array[2]) + parseInt(idcard_array[12])) * 10 
+ (parseInt(idcard_array[3]) + parseInt(idcard_array[13])) * 5 
+ (parseInt(idcard_array[4]) + parseInt(idcard_array[14])) * 8 
+ (parseInt(idcard_array[5]) + parseInt(idcard_array[15])) * 4 
+ (parseInt(idcard_array[6]) + parseInt(idcard_array[16])) * 2 
+ parseInt(idcard_array[7]) * 1 
+ parseInt(idcard_array[8]) * 6 
+ parseInt(idcard_array[9]) * 3 ; 
Y = S % 11; 
M = "F"; 
JYM = "10X98765432"; 
M = JYM.substr(Y,1);//判断校验位 
if(M == idcard_array[17]) return Errors[0]; //检测ID的校验位 
else return Errors[3]; 
} 
else return Errors[2]; 
break; 
default: 
return Errors[1]; 
break; 
} 

} 
alert(checkIdcard("220183198808081610")) 
</script> 

二、通过asp代码验证：

复制代码代码如下:

 
<% 
Function checkIDCard(idcard) '-1为正确的身份证，否则为非法身份证 

Dim Y, JYM 
Dim S, M 

Dim area 
area = "11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91" 
Dim ereg 
Set ereg = New regexp 

'地区检验 
If InStr(1, area, Mid(idcard, 1, 2)) = 0 Then checkIDCard = 1: Exit Function 

'身份号码位数及格式检验 
Select Case Len(idcard) 
Case 15 
If ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0 or ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 100 = 0 And (CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0)) Then 
ereg.Pattern = "^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$" ';//测试出生日期的合法性 
Else 
ereg.Pattern = "^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$" ';//测试出生日期的合法性 
End If 
If (ereg.test(idcard)) Then 
checkIDCard = -1 
Else 
checkIDCard = 2 
End If 
Case 18 
'//18位身份号码检测 
'//出生日期的合法性检查 
If ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0 or ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 100 = 0 And (CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0)) Then 
ereg.Pattern = "^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$" ';//闰年出生日期的合法性正则表达式 
Else 
ereg.Pattern = "^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$" ';//平年出生日期的合法性正则表达式 
End If 
If (ereg.test(idcard)) Then 
'//计算校验位 
S = (CInt(Mid(idcard, 0 + 1, 1)) + CInt(Mid(idcard, 10 + 1, 1))) * 7 _ 
+ (CInt(Mid(idcard, 1 + 1, 1)) + CInt(Mid(idcard, 11 + 1, 1))) * 9 _ 
+ (CInt(Mid(idcard, 2 + 1, 1)) + CInt(Mid(idcard, 12 + 1, 1))) * 10 _ 
+ (CInt(Mid(idcard, 3 + 1, 1)) + CInt(Mid(idcard, 13 + 1, 1))) * 5 _ 
+ (CInt(Mid(idcard, 4 + 1, 1)) + CInt(Mid(idcard, 14 + 1, 1))) * 8 _ 
+ (CInt(Mid(idcard, 5 + 1, 1)) + CInt(Mid(idcard, 15 + 1, 1))) * 4 _ 
+ (CInt(Mid(idcard, 6 + 1, 1)) + CInt(Mid(idcard, 16 + 1, 1))) * 2 _ 
+ CInt(Mid(idcard, 7 + 1, 1)) * 1 _ 
+ CInt(Mid(idcard, 8 + 1, 1)) * 6 _ 
+ CInt(Mid(idcard, 9 + 1, 1)) * 3 
Y = S Mod 11 
M = "F" 
JYM = "10X98765432" 
M = Mid(JYM, Y + 1, 1) 

If (M = Mid(idcard, 17 + 1, 1)) Then checkIDCard = -1 Else checkIDCard = 3 

Else 
checkIDCard = 4 
End If 

Case Else 
checkIDCard = Len(idcard) 
End Select 

End Function%> 