python实现的文件夹清理程序分享

151 阅读 0 评论 100 点赞

我是靠谱客的博主贪玩睫毛，最近开发中收集的这篇文章主要介绍python实现的文件夹清理程序分享，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

使用：

复制代码代码如下:

foldercleanup.py -d 10 -k c:\test\keepfile.txt c:\test

表示对c:\test目录只保留最近10天的子文件夹和keepfile.txt中指定的子文件夹。

代码：

复制代码代码如下:

import os
import os.path
import datetime

def getOption():
from optparse import OptionParser

des   = "clean up the folder with some options"
prog = "foldercleanup"
ver   = "%prog 0.0.1"
usage = "%prog [options] foldername"

p = OptionParser(description=des, prog=prog, version=ver, usage=usage,add_help_option=True)
p.add_option('-d','--days',action='store',type='string',dest='days',help="keep the subfolders which are created in recent %days% days")
p.add_option('-k','--keepfile',action='store',type='string',dest='keepfile',help="keep the subfolders which are recorded in text file %keepfile% ")
options, arguments = p.parse_args()

if len(arguments) != 1:
    print("error: must input one directory as only one parameter ")
    return

return options.days, options.keepfile, arguments[0]

def preCheckDir(dir):
if(not os.path.exists(dir)):
    print("error: the directory your input is not existed")
    return
if(not os.path.isdir(dir)):
    print ("error: the parameter your input is not a directory")
    return

return os.path.abspath(dir)

def isKeepByDay(dir, day):
indays = False
if( day is not None) :
    t = os.path.getctime(dir)
    today = datetime.date.today()
    createdate = datetime.date.fromtimestamp(t)
    indate = today - datetime.timedelta(days = int(day))
    print (createdate)
    if(createdate >= indate):
      indays = True
print (indays)
return indays

def isKeepByKeepfile(dir, keepfile):
needkeep = False
print (dir)
if (keepfile is not None):
    try :
      kf = open(keepfile,"r")
      for f in kf.readlines():
        print (f)
        if (dir.upper().endswith("\\" + f.strip().upper())):
          needkeep = True
      kf.close()
    except:
      print ("error: keep file cannot be opened")
print(needkeep)
return needkeep

def removeSubFolders(dir, day, keepfile):
subdirs = os.listdir(dir)
for subdir in subdirs:
    subdir = os.path.join(dir,subdir)
    if ( not os.path.isdir(subdir)):
      continue
    print("----------------------")
    if( (not isKeepByDay(subdir, day))and (not isKeepByKeepfile(subdir, keepfile))):
      print("remove subfolder: " + subdir)
      import shutil
      shutil.rmtree(subdir,True)

def FolderCleanUp():
(day, keepfile, dir) = getOption()
dir = preCheckDir(dir)
if dir is None:
    return
removeSubFolders(dir,day,keepfile)

if __name__=='__main__':
FolderCleanUp()

对目录下保留最后的zip文件：

复制代码代码如下:

def KeepLastNumZips(num)
def extractTime(f):
return os.path.getctime(f)

    zipfiles = [os.path.join(zipdir, f)
                for f in os.listdir(zipdir)
                if os.path.splitext(f)[1] == ".zip"]
    if len(zipfiles) > num:
        zipfiles.sort(key=extractTime, reverse=True)
        for i in range(num, len(zipfiles)):
            os.remove(zipfiles[i])