Python实现读取目录所有文件的文件名并保存到txt文件代码

145 阅读 0 评论 96 点赞

我是靠谱客的博主发嗲毛衣，最近开发中收集的这篇文章主要介绍Python实现读取目录所有文件的文件名并保存到txt文件代码，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

代码： (使用os.listdir)

复制代码代码如下:

import os

def ListFilesToTxt(dir,file,wildcard,recursion):
    exts = wildcard.split(" ")
    files = os.listdir(dir)
    for name in files:
        fullname=os.path.join(dir,name)
        if(os.path.isdir(fullname) & recursion):
            ListFilesToTxt(fullname,file,wildcard,recursion)
        else:
            for ext in exts:
                if(name.endswith(ext)):
                    file.write(name + "\n")
                    break

def Test():
dir="J:\\1"
outfile="binaries.txt"
wildcard = ".txt .exe .dll .lib"

file = open(outfile,"w")
if not file:
print ("cannot open the file %s for writing" % outfile)

ListFilesToTxt(dir,file,wildcard, 1)

file.close()

Test()

代码：(使用os.walk) walk递归地对目录及子目录处理，每次返回的三项分别为：当前递归的目录，当前递归的目录下的所有子目录，当前递归的目录下的所有文件。

复制代码代码如下:

import os

def ListFilesToTxt(dir,file,wildcard,recursion):
    exts = wildcard.split(" ")
    for root, subdirs, files in os.walk(dir):
        for name in files:
            for ext in exts:
                if(name.endswith(ext)):
                    file.write(name + "\n")
                    break
        if(not recursion):
            break

def Test():
dir="J:\\1"
outfile="binaries.txt"
wildcard = ".txt .exe .dll .lib"

file = open(outfile,"w")
if not file:
print ("cannot open the file %s for writing" % outfile)

ListFilesToTxt(dir,file,wildcard, 0)

file.close()

Test()