PHP 采集获取指定网址的内容

254 阅读 0 评论 168 点赞

我是靠谱客的博主健壮茉莉，最近开发中收集的这篇文章主要介绍PHP 采集获取指定网址的内容，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

参考别人想法变成自己的想法，你会发现慢慢下来以后你就拥有了临时解决很多问题的思路与方法。

复制代码代码如下:

<?php 
/* 
功能:获取页面内容,存储下来阅读; lost63 
*/ 
Class GetUrl{ 
var $url; //地址 
var $result; //结果 
var $content; //内容 
var $list; //列表 
function GetUrl($url){ 
$this->url=$url; 
$this->GetContent(); 
$this->GetList(); 
$this->FileSave(); 
//print_r($this->list[2]); 
} 
private function GetContent(){ 
$this->result=fopen($this->url,"r"); 
while(!feof($this->result)){ 
$this->content.=fgets($this->result,9999); 
} 
} 
private function GetList(){ 
preg_match_all('/<a(.*?)href="(.*?)">(.*?)<\/a>/',$this->content,$this->list); 
$this->list[2]=array_unique($this->list[2]); //移除相同的值 
while(list($key,$value)=each($this->list[2])){ 
if(strpos($value,".html")==0||strpos($value,"jiaocheng")==0){ 
unset($this->list[2][$key]); 
}else{ 
$this->list[2][$key]=substr($value,0,strpos($value,".html")).".html"; //去掉不需要的标签 
} 
} 
} 
private function FileSave(){ 
foreach($this->list[2] as $value){ 
$this->url=$value; //重新赋值 
$this->content=null; 
$this->GetContent(); //提取内容 
preg_match_all('/<title>(.*?)<\/title>/',$this->content,$files); //取标题 
$filename=$files[1][0].".html"; //存储名 
$content=$this->str_cut($this->content,'http://pagead2.googlesyndication.com/pagead/show_ads.js','<div id="article_detail">'); 
$file=fopen($filename,"w"); 
fwrite($file,$content); 
fclose($file); 
echo $filename."保存 OK<br>\n"; 
} 
} 
function str_cut($str ,$start, $end) { 
$content = strstr( $str, $start ); 
$content = substr( $content, strlen( $start ), strpos( $content, $end ) - strlen( $start ) ); 
return $content; 
} 
} 
$w=new GetUrl("http://www.ijavascript.cn/jiaocheng/javascript-jiaocheng-352.html"); 
?>