python列表对应元素合并为列表及判断一个列表是几维

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a=[1,2,3,4,5]
b=[2,3,4,5,6]
d=[]
for i in range(len(a)):
    c = []
    c.append(a[i])
    c.append(b[i])
    d.append(c)
print(d)

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date=[]
date_temp1=['1545225954.721;1545225955.115', '1545225955.215;1545225955.316;1545225955.422',
            '1545225955.708;1545225955.817;1545225955.916', '1545225956.230;1545225956.319']
date_temp2=[]
for i in range(len(date_temp1)):
    if date_temp1[i]:
        date_temp2.append(date_temp1[i].split(';'))
print(date_temp2)
for i in date_temp2:
    for j in i:
        date.append(j)
print(date)

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import numpy as np
X=[[0.1, 0.1], [0.2, 0.1], [0.1, 0.1]]
X2=[[[0.1,0.5], [0.1,0.8]]]
X1=[0.1,0.2, 0.1, 0.1, 0.1, 0.1]
L1=np.array(X1)
print(L1.shape)
print(len(L1.shape))
L=np.array(X)
print(L.shape)
print(len(L.shape))
L2=np.array(X2)
print(L2.shape)
print(len(L2.shape))
# 根据len判断，1表示一维，2表示二维，3表示3维

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date_lst=[]
for i in range(3):
    date_lst.append([])
print(date_lst)