AJAX之发送GET请求

复制代码用jquery发送get请求 function AjaxSubmit1() { $.ajax({ //用jQuery发送 url: '/app04/ajax1/', type: 'GET', data: {'p':123}, success:function () { } }) } 原生发送get请求 function AjaxSubmit2() { //原生发送请求 var xhr = new XMLHttpRequest(); xhr.onreadystatechange = function () { if (xhr.readyState == 4) { // 接收完毕服务器返回的数据 console.log(xhr.responseText); } }; xhr.open('GET', '/app04/ajax1?p=123'); xhr.send(null); }

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用jquery发送get请求
function AjaxSubmit1() {
$.ajax({
//用jQuery发送
url: '/app04/ajax1/',
type: 'GET',
data: {'p':123},
success:function () {
}
})
}
原生发送get请求
function AjaxSubmit2() {
//原生发送请求
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function () {
if (xhr.readyState == 4) {
// 接收完毕服务器返回的数据
console.log(xhr.responseText);
}
};
xhr.open('GET', '/app04/ajax1?p=123');
xhr.send(null);
}