ZJU-PAT 1065. A+B and C (64bit) (20)

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概述

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

分析：
1.考虑相加溢出的情况
(1)  a > 0 && b>0 && a+b <0  , 因 a+b > c，故true
(2)  a < 0 && b<0 && a+b >0 , 因 a+b < c，故false
2. PAT上不支持 __int64数据,采用long long型数据

#pragma warning (disable:4786)
#include<iostream>
#include<string>
#include<cstdio>
#include<algorithm>
#include<map>
using namespace std;
int main()
{
int T;
cin>>T;
for(int i=1;i<=T;i++)
{
long long int
a,b,c;
cin>>a>>b>>c;
cout<<"Case #"<<i+1<<": ";
bool flag;
long long ans =a+b;
if(a>0 && b>0 && ans<=0)
flag=true;
else if(a<0 && b <0 && ans >= 0)
flag=false;
else
flag = (ans > c);
if(flag)
cout<<"true"<<endl;
else
cout<<"false"<<endl;
}
return 0;
}