A + B Again（2057）A + B Again

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概述

A + B Again

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 15133 Accepted Submission(s): 6602

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output

For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

  
  
   
   +A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output

  
  
   
   0
2C
11
-2C
-90
  
  
  
  

  
  
  
  
   
   --------------------------------------------------------
  
  
  
  

  
  
  
  
   
   #include<stdio.h>


int main()
{

   
   	__int64 a,b;

   
   	while(scanf("%I64x %I64x",&a,&b)!=EOF)   //x大小写都可以编译成功，但只有大写时才AC。

   
   	{

   
   		b+=a;

   
   		if(b<0)

   
   		{

   
   			b=-b;

   
   			printf("-");

   
   		}

   
   		printf("%I64xn",b);

   
   	}

   
   	return 0;
}