python按照字符串长度排序,根据字符串的长度对Python列表进行排序

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I want to sort a list of strings based on the string length. I tried to use sort as follows, but it doesn't seem to give me correct result.

xs = ['dddd','a','bb','ccc']

print xs

xs.sort(lambda x,y: len(x) < len(y))

print xs

['dddd', 'a', 'bb', 'ccc']

What might be wrong?

解决方案

When you pass a lambda to sort, you need to return an integer, not a boolean. So your code should instead read as follows:

xs.sort(lambda x,y: cmp(len(x), len(y)))

Note that cmp is a builtin function such that cmp(x, y) returns -1 if x is less than y, 0 if x is equal to y, and 1 if x is greater than y.

Of course, you can instead use the key parameter:

xs.sort(key = lambda s: len(s))</

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