python将一句话重复n次输出_如何仅使用itertools将Python列表的每个元素重复n次？...

I have a list with numbers:

numbers = [1, 2, 3, 4].

I would like to have a list where they repeat n times like so (for n = 3):

[1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4].

The problem is that I would like to only use itertools for this, since I am very constrained in performance.

I tried to use this expression:

list(itertools.chain.from_iterable(itertools.repeat(numbers, 3)))

But it gives me this kind of result:

[1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4]

which is obviously not what I need.

Is there a way to do this with itertools only, without using sorting, loops and list comprehensions? The closest I could get is:

list(itertools.chain.from_iterable([itertools.repeat(i, 3) for i in numbers])),

but it also uses list comprehension, which I would like to avoid.

解决方案

Since you don't want to use list comprehension, following is a pure (+zip) itertools method to do it -

from itertools import chain, repeat

list(chain.from_iterable(zip(*repeat(numbers, 3))))

# [1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4]