我是靠谱客的博主 难过电脑,最近开发中收集的这篇文章主要介绍Invocation of init method failed; nested exception is java.lang.NoSuchMethodError:运行错误 解决,觉得挺不错的,现在分享给大家,希望可以做个参考。

概述

运行错误

***************************
APPLICATION FAILED TO START
***************************

Description:

An attempt was made to call a method that does not exist. The attempt was made from the following location:

    org.springframework.scheduling.quartz.SchedulerAccessor.registerListeners(SchedulerAccessor.java:351)

The following method did not exist:

    org.quartz.Scheduler.getListenerManager()Lorg/quartz/ListenerManager;

The method's class, org.quartz.Scheduler, is available from the following locations:

    jar:file:/D:/repository/org/opensymphony/quartz/quartz/1.6.1/quartz-1.6.1.jar!/org/quartz/Scheduler.class

It was loaded from the following location:

    file:/D:/repository/org/opensymphony/quartz/quartz/1.6.1/quartz-1.6.1.jar


Action:

Correct the classpath of your application so that it contains a single, compatible version of org.quartz.Scheduler

分析:之前好好的可以运行突然不行了,看报错可能是定时任务的jar包冲突导致了

1、全局查一下发现shiro-all有引入该jar包

 解决

       查询依赖的时候发现它是shiro的一个可选项,直接把它exclusion。

<dependency>
    <groupId>org.apache.shiro</groupId>
    <artifactId>shiro-all</artifactId>
    <version>1.4.0</version>
    <exclusions>
        <exclusion>
            <groupId>org.apache.shiro</groupId>
            <artifactId>shiro-quartz</artifactId>
        </exclusion>
    </exclusions>
</dependency>

若shiro-all 封装在jar包中引入,则可将下面代码放入该项目引入的父级包下

     <exclusions>
        <exclusion>
            <groupId>org.apache.shiro</groupId>
            <artifactId>shiro-quartz</artifactId>
        </exclusion>
    </exclusions>

最后

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