我是靠谱客的博主 热情大炮,最近开发中收集的这篇文章主要介绍CodeForces - 271A,觉得挺不错的,现在分享给大家,希望可以做个参考。

概述

It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.


Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples

Input

1987

Output

2013

Input

2013

Output

2014
题目简述: 给定一个年份,找出在此年份之后最近的年份上的数字都不相同的年份(如1987)
题目思路: 将年份的数字拆成单个,比较数字是否有相同的。
AC代码如下:

#include<iostream>
#include<stdio.h>
using namespace std;
int main()
{
int n;
scanf_s("%d", &n);
int a, b, c, d;
for (int i = n + 1; i < 10000; i++)
{
a = i / 1000;
b = i / 100 % 10;
c = i / 10 % 10;
d = i % 10;
if (a != b && a != c && a != d && b != c && b != d && c != d)
{
printf("%d", i);
break;
}
}
return 0;
}

最后

以上就是热情大炮为你收集整理的CodeForces - 271A的全部内容,希望文章能够帮你解决CodeForces - 271A所遇到的程序开发问题。

如果觉得靠谱客网站的内容还不错,欢迎将靠谱客网站推荐给程序员好友。

本图文内容来源于网友提供,作为学习参考使用,或来自网络收集整理,版权属于原作者所有。
点赞(62)

评论列表共有 0 条评论

立即
投稿
返回
顶部