在bash中仅使用l列出目录：检查

本文翻译自：Listing only directories using ls in bash: An examination

This command lists directories in the current path: ls -d */ 此命令列出当前路径中的目录： ls -d */

What exactly does the pattern */ do? */模式到底是做什么的？

And how can we give the absolute path in the above command (eg ls -d /home/alice/Documents ) for listing only directories in that path? 以及如何在上述命令中给出绝对路径（例如ls -d /home/alice/Documents ）以仅列出该路径中的目录？

#1楼

参考：https://stackoom.com/question/yDgY/在bash中仅使用l列出目录-检查

#2楼

*/ is a pattern that matches all of the subdirectories in the current directory ( * would match all files and subdirectories; the / restricts it to directories). */是与当前目录中所有子目录匹配的模式（ *将与所有文件和子目录匹配； /将其限制为目录）。 Similarly, to list all subdirectories under /home/alice/Documents, use ls -d /home/alice/Documents/*/ 同样，要列出/ home / alice / Documents下的所有子目录，请使用ls -d /home/alice/Documents/*/

#3楼

Four ways to get this done, each with a different output format 完成此操作的四种方法，每种方法具有不同的输出格式

1. Using echo 1.使用echo

Example: echo */ , echo */*/ 示例： echo */ ， echo */*/
Here is what I got: 这是我得到的：

1
2
3
cs/ draft/ files/ hacks/ masters/ static/
cs/code/ files/images/ static/images/ static/stylesheets/

2. Using ls only 2.仅使用ls

Example: ls -d */ 示例： ls -d */
Here is exactly what I got: 这正是我得到的：

1
2
3
4
5
6
7
cs/
files/
masters/
draft/
hacks/
static/

Or as list (with detail info): ls -dl */ 或作为列表（包含详细信息）： ls -dl */

3. Using ls and grep 3.使用ls和grep

Example: ls -l | grep "^d" 示例： ls -l | grep "^d" ls -l | grep "^d" Here is what I got: ls -l | grep "^d"这是我得到的：

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
drwxr-xr-x
24 h
staff
816 Jun
8 10:55 cs
drwxr-xr-x
6 h
staff
204 Jun
8 10:55 draft
drwxr-xr-x
9 h
staff
306 Jun
8 10:55 files
drwxr-xr-x
2 h
staff
68 Jun
9 13:19 hacks
drwxr-xr-x
6 h
staff
204 Jun
8 10:55 masters
drwxr-xr-x
4 h
staff
136 Jun
8 10:55 static

4. Bash Script (Not recommended for filename containing spaces) 4. Bash脚本（不建议将文件名包含空格）

Example: for i in $(ls -d */); do echo ${i%%/}; done 示例： for i in $(ls -d */); do echo ${i%%/}; done for i in $(ls -d */); do echo ${i%%/}; done
Here is what I got: 这是我得到的：

1
2
3
4
5
6
7
cs
draft
files
hacks
masters
static

If you like to have '/' as ending character, the command will be: for i in $(ls -d */); do echo ${i}; done 如果您希望以'/'作为结束字符，则命令将为： for i in $(ls -d */); do echo ${i}; done for i in $(ls -d */); do echo ${i}; done

1
2
3
4
5
6
7
cs/
draft/
files/
hacks/
masters/
static/

#4楼

I use: 我用：

1
2
ls -d */ | cut -f1 -d'/'

This creates a single column with no trailing slash - useful in scripts. 这将创建不带斜杠的单列-在脚本中很有用。

My two cents. 我的两分钱。

#5楼

I partially solved with : 我部分解决了：

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
cd "/path/to/pricipal/folder"
for i in $(ls -d .*/); do sudo ln -s "$PWD"/${i%%/} /home/inukaze/${i%%/}; done
ln: «/home/inukaze/./.»: can't overwrite a directory
ln: «/home/inukaze/../..»: can't overwrite a directory
ln: accesing to «/home/inukaze/.config»: too much symbolics links levels
ln: accesing to «/home/inukaze/.disruptive»: too much symbolics links levels
ln: accesing to «/home/inukaze/innovations»: too much symbolics links levels
ln: accesing to «/home/inukaze/sarl»: too much symbolics links levels
ln: accesing to «/home/inukaze/.e_old»: too much symbolics links levels
ln: accesing to «/home/inukaze/.gnome2_private»: too much symbolics links levels
ln: accesing to «/home/inukaze/.gvfs»: too much symbolics links levels
ln: accesing to «/home/inukaze/.kde»: too much symbolics links levels
ln: accesing to «/home/inukaze/.local»: too much symbolics links levels
ln: accesing to «/home/inukaze/.xVideoServiceThief»: too much symbolics links levels

Well , this reduce to me , the mayor part :) 好吧，这减少了我，市长的一部分:)

#6楼

One-liner to list directories only from "here". 一线式仅从“这里”列出目录。

With file count. 随着文件数。

1
2
for i in `ls -d */`; do g=`find ./$i -type f -print| wc -l`; echo "Directory $i contains $g files."; done

最后

以上就是爱笑西牛最近收集整理的关于在bash中仅使用l列出目录：检查的全部内容，更多相关在bash中仅使用l列出目录内容请搜索靠谱客的其他文章。