php mysql 重复提交数据,PHP两次将数据插入到MySQL中，而不是一次

$servername = "localhost";

$username = "root";

$password = "pass";

$dbname = "test";

$name="admin";

$pass="passerino";

// Create connection

$conn = new mysqli($servername, $username, $password, $dbname);

if ($conn->connect_error) {

die("Connection failed: " . $conn->connect_error);

}else {

echo nl2br("Conected n");

}

$sqlin="INSERT INTO data_test (username, password) VALUES ('valname','valpass')";

$result=$conn->query($sqlin);

if ($conn->query($sqlin) === TRUE) {

echo "New record created successfully";

} else {

echo "Error: " . $sqlin . "
" . $conn->error;

}

$conn->close();

include_once "read.php";

?>

Hello i have this simple .php file to insert data into mySQL database,but instead of once it does it two times with one request.How can i stop this?I am using wamp server x64,chrome,php 5.5.12;

P.S read.php displays the data table

解决方案

change this code

$sqlin="INSERT INTO data_test (username, password) VALUES ('valname','valpass')";

$result=$conn->query($sqlin);

if ($conn->query($sqlin) === TRUE) {

echo "New record created successfully";

} else {

echo "Error: " . $sqlin . "
" . $conn->error;

}

$conn->close();

include_once "read.php";

to

$sqlin="INSERT INTO data_test (username, password) VALUES ('valname','valpass')";

$result=$conn->query($sqlin);

if ($result === TRUE) {

echo "New record created successfully";

} else {

echo "Error: " . $sqlin . "
" . $conn->error;

}

$conn->close();

include_once "read.php";

Because if you run this line $conn->query($sqlin); twice it will run your query twice and insert record in database two time