我是靠谱客的博主 凶狠雪碧,这篇文章主要介绍python datatime 平均值_计算python datetime的平均值,现在分享给大家,希望可以做个参考。

I have a datetime attribute:

d = {

'DOB': pd.Series([

datetime.datetime(2014, 7, 9),

datetime.datetime(2014, 7, 15),

np.datetime64('NaT')

], index=['a', 'b', 'c'])

}

df_test = pd.DataFrame(d)

I would like to compute the mean for that attribute. Running mean() causes an error:

TypeError: reduction operation 'mean' not allowed for this dtype

I also tried the solution proposed elsewhere. It doesn't work as running the function proposed there causes

OverflowError: Python int too large to convert to C long

What would you propose? The result for the above dataframe should be equivalent to

datetime.datetime(2014, 7, 12).

解决方案

You can take the mean of Timedelta. So find the minimum value and subtract it from the series to get a series of Timedelta. Then take the mean and add it back to the minimum.

dob = df_test.DOB

m = dob.min()

(m + (dob - m).mean()).to_pydatetime()

datetime.datetime(2014, 7, 12, 0, 0)

One-line

df_test.DOB.pipe(lambda d: (lambda m: m + (d - m).mean())(d.min())).to_pydatetime()

I use the epoch pd.Timestamp(0) instead of min

df_test.DOB.pipe(lambda d: (lambda m: m + (d - m).mean())(pd.Timestamp(0))).to_pydatetime()

最后

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