python遍历一个列表匹配另一个列表,Python：将一个列表中的值匹配到另一个列表中的值序列...

I have two lists.

e_list = [('edward', '1.2.3.4.'), ('jane','1.2.3.4.'), ('jackie', '2.3.4.10.')...]

and a_list (the main list to be checked against)

a_list = [('a', '1.2.3.'), ('b', '2.3.'), ('c', '2.3.4.')...]

I'd like a modified output to my original question. I'm unsure of how I'd change the code snippet to solve the same question but to output all possibilities?

e.g.

new_list = [ ('edward', '1.2.3.4', '1.2.3'), ('jane', '1.2.3.4.', '1.2.3'), ('jackie', '2.3.4.10.', '2.3.'), ('jackie', '2.3.4.10.', '2.3.4')]

解决方案

You can use list comprehension if you want:

res = [(name, digits, match) for name, digits in e_list

for _, match in a_list

if digits.startswith(match)]

print res

But since it gets complicated, nested loops may be cleaner. You can use yield to get final list:

def get_res():

for name, digits in e_list:

for _, match in a_list:

if digits.startswith(match):

yield name, digits, match

print list(get_res())