我是靠谱客的博主 斯文黑米,最近开发中收集的这篇文章主要介绍Dev c++自带小游戏,觉得挺不错的,现在分享给大家,希望可以做个参考。

概述

先点击左上方的“文件”,再点击“新建”,接着点击“项目”,就会有下面的样子:

再选Console,就会出现下面的样子:

 接着选Jackpot,再点确定,C++就会打开一个mian,这时你运行就是了。
游戏意思:输入一个数字,杰克会告诉你太大了或太小了,直到猜中或次数用完。
懒的人可以复制下面的代码:

#include <iostream>
#include <stdlib.h>
#include <time.h>

using namespace std;

void Start();
void GetResults();

int i, j, life, maxrand;
char c;

void Start() {
	i = 0;
	j = 0;
	life = 0;
	maxrand = 6;
	
	cout << "Select difficulty mode:n"; // the user has to select a difficutly level
	cout << "1 : Easy (0-15)n";
	cout << "2 : Medium (0-30)n";
	cout << "3 : Difficult (0-50)n";
	cout << "or type another key to quitn";
	c = 30;

	cin >> c;                   // read the user's choice
	cout << "n";

	switch (c) {
		case '1':
			maxrand = 15;  // the random number will be between 0 and maxrand
			break;
		case '2':
			maxrand = 30;
			break;
		case '3':
			maxrand = 50;
			break;
		default:
			exit(0);
		break;
	}

	life = 5;         // number of lifes of the player
	srand((unsigned)time(NULL)); // init Rand() function
	j = rand() % maxrand;  // j get a random value between 0 and maxrand
	
	GetResults();
}

void GetResults() {
	if (life <= 0) { // if player has no more life then he loses
		cout << "You lose !nn";
		Start();
	}

	cout << "Type a number: n";
	cin >> i;
	
	if((i>maxrand) || (i<0)) { // if the user number isn't correct, restart
		cout << "Error: number not between 0 and n" << maxrand;
		GetResults();
	}

	if(i == j) {
		cout << "YOU WIN!nn"; // the user found the secret number
		Start();
	} else if(i>j) {
		cout << "Too BIGn";
		life = life - 1;
		cout << "Lives remaining: " << life << "nn";
		GetResults();
	} else if(i<j) {
		cout << "Too SMALLn";
		life = life - 1;
		cout << "Lives remaining: " << life << "nn";
		GetResults();
	}
}

int main() {
	cout << "** Jackpot game **n";
	cout << "The goal of this game is to guess a number.n";
	cout << "Jackpot will tell you if the number is too big or toon";
	cout << "small compared to the secret number to find.nn";
	Start();
	return 0;
}

最后

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