Integer Inquiry

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概述

E - Integer Inquiry

Crawling in process... Crawling failed Time Limit:1000MS Memory Limit:10000KB 64bit IO Format:%lld & %llu

Submit Status

Description

Input

Output

Sample Input

Sample Output

Hint

Description

As a recruiting ploy, Google once posted billboards in Harvard Square and in the Silicon Valley area just stating “{first 10-digit prime found in consecutive digits of e}.com”. In other words, find that 10-digit sequence and then connect to the web site — and find out that Google is trying to hire people who can solve a particular kind of problem.

Not to be outdone, Gaggle (a loosy-goosy fuzzy logic search firm), has devised its own recruiting problem. Consider the base 7 expansion of a rational number. For example, the first few digits of the base 7 expansion of 1/5 ₁₀ = 0.12541... ₇, 33/4 ₁₀ = 11.15151... ₇, and 6/49 ₁₀ = 0.06000... ₇, From this expansion, find the digits in a particular range of positions to the right of the "decimal" point.

Input

The input file begins with a line containing a single integer specifying the number of problem sets in the file. Each problem set is specified by four base 10 numbers on a single line, n d b e, where n and d are the numerator and denominator of the rational number and 0 <= n <= 5,000 and 1 <= d <= 5,000. b and e are the beginning and ending positions for the desired range of digits, with 0 <= b,e <= 250 and 0 <= (e-b) <= 20. Note that 0 is the position immediately to the right of the decimal point.

Output

Each problem set will be numbered (beginning at one) and will generate a single line:

Problem set k: n / d, base 7 digits b through e: result

where k is replaced by the problem set number, result is your computed result, and the other values are the corresponding input values.

Sample Input

4
1 5 0 0
6 49 1 3
33 4 2 7
511 977 122 126

Sample Output

Problem set 1: 1 / 5, base 7 digits 0 through 0: 1
Problem set 2: 6 / 49, base 7 digits 1 through 3: 600
Problem set 3: 33 / 4, base 7 digits 2 through 7: 151515
Problem set 4: 511 / 977, base 7 digits 122 through 126: 12425

Hint

Description

One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers.
``This supercomputer is great,'' remarked Chip. ``I only wish Timothy were here to see these results.'' (Chip moved to a new apartment, once one became available on the third floor of the Lemon Sky apartments on Third Street.)

Input

The input will consist of at most 100 lines of text, each of which contains a single VeryLongInteger. Each VeryLongInteger will be 100 or fewer characters in length, and will only contain digits (no VeryLongInteger will be negative).

The final input line will contain a single zero on a line by itself.

Output

Your program should output the sum of the VeryLongIntegers given in the input.

Sample Input

123456789012345678901234567890
123456789012345678901234567890
123456789012345678901234567890
0

Sample Output

370370367037037036703703703670

#include<stdio.h>
#include<string.h>
#define N 103

char capten[N];
char temp[N];
void shift(char *a);

int main()
{
	int carry,i;
	char tp;
	memset(capten,'0',sizeof(capten));
	/*for(i=0;i<N;i++)
	printf("%c",capten[i]);
	printf("n");*/
	while(gets(temp) && (strlen(temp)!=1 || temp[0]!='0')){
		carry=0;
		shift(temp);
		/*for(i=0;i<N;i++)
		printf("%c",temp[i]);
		printf("n");*/
		for(i=N-1;i>=0;i--){
			tp=capten[i];
			capten[i]= (carry+(capten[i]-'0')+(temp[i]-'0')) % 10 +'0';
			carry= (carry+(tp-'0')+(temp[i]-'0'))/10;
		}
	}
	for(i=0;;i++)
	if(capten[i] != '0')
	break;
	for(i;i<N;i++)
	printf("%c",capten[i]);
	printf("n");
	return 0;
}

void shift(char *a)
{
	int len=strlen(a);
	int k=len-1;
	int i;
	int gap=N-len;
	for(k;k>=0;k--){
		a[k+gap]=a[k];
	}
	for(i=0;i<gap;i++){
		a[i]='0';
	}
}