实现Time类中的运算符重载

/* (程序头部注释开始)
* 程序的版权和版本声明部分
* Copyright (c) 2011, 烟台大学计算机学院学生
* All rights reserved.
* 文件名称：                             
* 作    者：             苗影                
* 完成日期：       2012  年      4 月   10     日
* 版 本 号：          

* 对任务及求解方法的描述部分
* 输入描述：
* 问题描述：
* 程序输出：
* 程序头部的注释结束
*/

#include <iostream>
using namespace std;
class CTime
{
private:
unsigned short int hour;
// 时
unsigned short int minute;
// 分
unsigned short int second;
// 秒
public:
CTime(int h=0,int m=0,int s=0):hour(h),minute(m),second(s){}
void setTime(int h,int m,int s);
void display();
//比较运算符(二目)的重载
bool operator > (CTime &t);
bool operator < (CTime &t);
bool operator >= (CTime &t);
bool operator <= (CTime &t);
bool operator == (CTime &t);
bool operator != (CTime &t);
//二目运算符的重载
CTime operator+(CTime &c);//返回c所规定的时、分、秒后的时间，例t1(8,20,25),t2(11,20,50)，t1+t2为:41:15
CTime operator-(CTime &c);//对照+理解
CTime operator+(int h);//返回s秒后的时间
CTime operator-(int h);//返回s秒前的时间
//一目运算符的重载
CTime operator++(int);//后置++，下一秒
CTime operator++();//前置++，下一秒
CTime operator--(int);//后置--，前一秒
CTime operator--();//前置--，前一秒
//赋值运算符的重载
CTime operator+=(CTime &c);
CTime operator-=(CTime &c);
CTime operator+=(int h);//返回s秒后的时间
CTime operator-=(int h);//返回s秒前的时间
};
//下面实现所有的运算符重载代码。
//为简化编程，请注意通过调用已有函数，利用好各函数之间的关系
void CTime::setTime(int h,int m,int s)
{
hour=h;
minute=m;
second=s;
}
void CTime::display()
{
cout<<hour<<":"<<minute<<":"<<second<<endl;
}
bool CTime::operator>(CTime &t)
{
if(hour * 3600 + minute * 60 + second > t.hour * 3600 + t.minute * 60 + second)
{
return true;
}
else
{
return false;
}
}
bool CTime::operator<(CTime &t)
{
if(hour * 3600 + minute * 60 + second < t.hour * 3600 + t.minute * 60 + second)
{
return true;
}
else
{
return false;
}
}
bool CTime::operator>=(CTime &t)
{
if(hour * 3600 + minute * 60 + second >= t.hour * 3600 + t.minute * 60 + second)
{
return true;
}
else
{
return false;
}
}
bool CTime::operator<=(CTime &t)
{
if(hour * 3600 + minute * 60 + second <= t.hour * 3600 + t.minute * 60 + second)
{
return true;
}
else
{
return false;
}
}
bool CTime::operator==(CTime &t)
{
if(hour * 3600 + minute * 60 + second == t.hour * 3600 + t.minute * 60 + second)
{
return true;
}
else
{
return false;
}
}
bool CTime::operator!=(CTime &t)
{
if(hour * 3600 + minute * 60 + second != t.hour * 3600 + t.minute * 60 + second)
{
return true;
}
else
{
return false;
}
}
CTime CTime::operator+(CTime &c)
{
hour=c.hour+hour;
minute=c.minute+minute;
second=c.second+second;
if (second>60)
{
minute=minute+(second/60);
second=second%60;
}
if(minute>60)
{
minute=minute%60;
hour=hour+minute/60;
}
if(hour>24)
{
hour=hour%24;
}
return (*this);
}
CTime CTime::operator-(CTime &c)
{
if(c.second<second)
{
minute=minute-1;
second=c.second+60-second;
}
else
{
second=c.second-second;
}
if(c.minute<minute)
{
hour=hour-1;
minute=c.minute+60-minute;
}
else
{
minute=c.minute-minute;
}
hour=c.hour-hour;
return (*this);
}
CTime CTime::operator+(int h)
{
second=second+hour;
if(second>60)
{
second=second%60;
minute=minute+second/60;
}
if(minute>60)
{
minute=minute%60;
minute=minute+minute/60;
}
if(hour>24)
{
hour= hour%24;
}
return (*this);
}
CTime CTime::operator-(int h)
{
int T;
T = hour * 3600 + minute *60 + second - h;
hour = T / 3600;
T = T % 3600;
minute = T / 60;
second = T % 60;
return (*this);
}
CTime CTime::operator ++(int )
{
return *this;
*this+1;
}
CTime CTime::operator ++()
{
*this+1;
return *this;
}
CTime CTime::operator --(int )
{
return*this;
*this-1;
}
CTime CTime::operator --()
{
*this-1;
return*this;
}
CTime CTime::operator+=(CTime &c)
{
return(*this+c );
}
CTime CTime::operator-=(CTime &c)
{
return(*this-c);
}
CTime CTime::operator+=(int h)
{
return(*this+h);
}
CTime CTime::operator-=(int h)
{
return (*this-h);
}
void main()
{
CTime t1(8,20,25),t2(11,20,50),t;
cout<<"t1为：";
t1.display();
cout<<"t2为：";
t2.display();
cout<<"下面比较两个时间大小：n";
if (t1>t2) cout<<"t1>t2"<<endl;
if (t1<t2) cout<<"t1<t2"<<endl;
if (t1==t2) cout<<"t1＝t2"<<endl;
if (t1!=t2) cout<<"t1≠t2"<<endl;
if (t1>=t2) cout<<"t1≥t2"<<endl;
if (t1<=t2) cout<<"t1≤t2"<<endl;
cout<<endl;
//下面自行设计对其他运算符的重载的测试
t = t1;
t = t + t2;
cout << "t1 + t2 = ";
t.display();
t = t1;
t = t - t2;
cout << "t1 - t2 = ";
t.display();
t = t1;
t = t + 5;
cout<< "t1 + 5 = ";
t .display();
t = t2;
t = t - 5;
cout<< "t2 - 5 = " ;
t.display();
t = t1;
t = t ++;
cout << endl;
cout << "t1++ = ";
t.display();
t = t1;
t = ++t;
cout << "++t1 = ";
t.display();
t = t2;
t = t --;
cout << "t1-- = ";
t.display();
t = t2;
t = --t;
cout << "--t1 = ";
t.display();
t = t1;
t +=t2;
cout << "t1 += t2,t1 = " ;
t.display();
t = t1;
t -= t2;
cout << "t1 -= t2,t1 = " ;
t.display();
t = t1;
t += 5;
cout << "t1 += 8 = " ;
t.display();
t = t1;
t -= 6;
cout << "t1 -= 6 = " ;
t.display();
system("pause");
}

经验积累：在做减法时，可以先把他们都化成秒，再变成时，分输出。

                要好好理解++i和i++的区别。

最后

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