C/C++中取得当前文件名与行数

60 阅读 0 评论 40 点赞

我是靠谱客的博主风中大碗，最近开发中收集的这篇文章主要介绍C/C++中取得当前文件名与行数，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

C/C++中取得当前文件名与行数

2007-10-16 13:40

Key Words：__FILE__ ，__LINE__ ， File Name ， Line Number

在C/C++中可以直接使用__FILE__ 和__LINE__取得当前的文件路径与代码的当前行数
参考如下：

/*===========================================*/

#include <iostream>
#include <string.h>

using namespace std;

const char * GetFileName( const char* path,const char* sep)
{
    const char * temp,* cRet;
    int cnt = 0;
    temp = path;
    cRet = NULL;

cnt = strlen(path);

    if( NULL == temp)
    {
       cout<<"The File Path is NULL."<<endl;
       return cRet;
    }
    if( NULL == sep )
    {
       cout<<"The Separate is NULL."<<endl;
       return cRet;
    }

    for(int i = 0;i<cnt;i++,temp++)
    {
      if( *temp == *sep )
        {
          cRet = temp + 1;
        }
    }

return cRet;
}

void PrintLineNum( long line )
{
cout<<"The Line Num is:"<<line<<endl;
}

int main()
{
char temp;
const char * pFile = NULL;

cout<<"The file path is: "__FILE__<<endl;

pFile = GetFileName( __FILE__ ,"//" );

    cout<<"The File Name Is :"<<pFile<<endl;
    // cout<<"The File Name Is :"<<*pFile<<endl;
    // attention please "pFile" cannot be "*pFile"
    // or else the result to be output will be the first character of the file name

PrintLineNum( __LINE__ );

    // just to have a pause
    cout<<"Enter any thing to exit!"<<endl;
    cin>>temp;
    return 0;
}

/*===========================================*/

该程序的执行结果如下：

The file path is: C:/Documents and Settings/wood/デスクトップ/test/test.cpp
The File Name Is :test.cpp
The Line Num is:56
Enter any thing to exit!