【C/C++业务】UNIX时间戳与正常时间相互转换

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#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>
#include <string>
#include <iostream>
using namespace std;

//str : 20201030
int time2unix(string str)
{
    struct tm time;
    time_t t;
    if (str.length() != 8)
        return 0;
    time.tm_year = atoi(str.substr(0, 4).c_str()) - 1900; /* 年份修正 */
    time.tm_mon = atoi(str.substr(4, 2).c_str()) - 1;     /* 月份修正 */
    time.tm_mday = atoi(str.substr(6, 2).c_str());
    time.tm_hour = 0;
    time.tm_min = 0;
    time.tm_sec = 0;
    t = mktime(&time);
    return (int)t;
}

string unix2time(int n,int format)
{
    char s[100] = {0};
    memset(s, 0, 100);
    time_t tick = (time_t)(n);
    struct tm *tm = localtime(&tick);
	switch (format)
	{
		case TIEM_TYPE_DATE:	//DATA:	20201030
		    strftime(s, sizeof(s), "%Y%m%d", tm);
			break;
		default: //TIME: 2020-10-30 10:10:10
			strftime(s, sizeof(s), "%Y-%m-%d %H:%M:%S", tm);
			break;
	}
    return string(s);
}

int main()
{
    string ret;
    string str = "20200131";
    int a = 0;
    a = time2unix(str);
    cout << a << endl;
    if (a == 0)
        ret = unix2time(a);
    else
    {
        a += 86400;
        ret = unix2time(a);
    }
    cout << ret << endl;
}

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int hex_to_dec(char* a)
{
	int len = strlen(a);
	int sum = 0;
	for (int i = 0; i < len; i++)
	{
		if (a[i] >= 'A' && a[i] <= 'F')
		{
			a[i] = int(a[i] - 'A') + 10 + '0';
		}

		if (a[i] >= 'a' && a[i] <= 'f')
		{
			a[i] = int(a[i] - 'a') + 10 + '0';
		}
		sum += (a[i] - '0') * (pow(16.0, len - 1 - i));
	}
	return sum;
}