用jquery实现，表单input按回车进入下一个input

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我是靠谱客的博主虚幻羽毛，最近开发中收集的这篇文章主要介绍用jquery实现，表单input按回车进入下一个input，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述


<!doctype html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Document</title>
<script src='js/jquery-1.10.2.min.js'></script>
<script>
$(function(){
$('#form1').on('keydown','input',function(e){
e = e || window.event;
var key = e.keyCode || e.which || e.charCode;
if(key == 13){
var inputarray =
$('#form1 input');
nextindex = inputarray.index(this)+1;
if (nextindex>=inputarray.length)
{
nextindex=nextindex-1;
}
next = inputarray[nextindex];
next.focus();
}
return false;
});
})	
</script>
</head>
<body>
<form action="" name='form1'
id='form1' method="post" >
<input type="text" name='user1' value='admin1' /><br/>
<input type="text" name='user2' value='admin2'/><br/>
<input type="text" name='user3' value='admin3'/><br/>
<input type="text" name='user4' value='admin4'/><br/>
<input type="text" name='user5' value='admin5' /><br/>
<textarea name="content" id="content" cols="30" rows="10"></textarea>
<button> ok </button>
</form>
</body>
</html>