分数矩阵 找规律#include#include#includeint n;double SUM( ){ double sum = 0; sum = n; for( int i = 2; i <= n; ++i ) { sum += ( n - i + 1 ) * 1.0 / i * 2; acm 2024-05-08 123 点赞 1 评论 186 浏览
